@Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. DateGroup. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. About; Products. Anybody help what is the equivalent of Dateadd and Datediff in DBeaver or anybody can convert this code in DBeaver. What's the function in Oracle that would be the equivalent to DATEDIFF in the SQL Server? On Oracle, it is an arithmetic issue: Select DATE1-DATE2 from dual Converting a raw number of days into a number of weeks and days is pretty simple. If the dates are really timestamps, then this is easy - subtract them and the result is a day to second interval. HQL Date format in Oracle / PostgreSQL: select TO_CHAR. Also, you need to put your dates into single quotes: use '2-2-2011' instead of simply 2-2-2011. Of course, if you need days instead of months, you can simply subtract one date from another, e. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. Finally, we will use a CASE statement. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. 9. (year/month/date from date) //oracle function for extracting values from date. Then it calculates the number of months that have passed until your given date (@test) by fours steps: 1. The part to return. for example, if SomeDate is 10/12/2007, that will return 12/31/2007. ) The dates and their formats are separated by a comma (,) and are defined in the Data field of the. first weeks into oracle. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. And this may raise an issue for leapers (someone born on the 29th of Feb), as taken from Wikipedia: The effective legal date of a leapling's birthday in non-leap years varies between jurisdictions. I want to select some data from one table if a date from another table is at least 6 months before today. Each Standard calendar week is defined to start on Sunday and it spans 7 days. Syntax. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. That is, this function returns the count (as a signed integer value) of the specified datepart boundaries crossed between the specified start date and end date. "Order Date") Description: Adds a specified number of intervals to a timestamp, and returns a single. 1. Sorted by: 3. If month is the same in both dates: results for month is negative. Valid values can be: DD, which computes the difference in days. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. 2188940092 Example 2 Date 1: 10th March 2011 Date 2: 1st Feb 2011 MONTHS_BETWEEN = 1. So far I have this: SELECT evnt. I didn’t know you answered questions including MySQL and. You will see column tools as one of the tabs. it does not give me the records marked with a date '17-JAN-02'. AT TIME ZONE. The @DATEDIFF calculation function for Essbase returns the difference between two input dates. 15 between 2 values that are 1 year, 1 month and 15 days apart. You need to add 1 to the DATEDIFF function and it will work as you want. You may: count the number of 24h elapsed time: day+1 - day = 1 day = 24h. ;-). sql. Once you have the date difference, you can use simple. DOW: returns the day of the week, between Sunday (0) and Saturday (6) DOY: returns the day of the year. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. DATEDIFF(Day, MIN(joindate), MAX(joindate)) AS DateDifferen. Justin, the example which you gave, if that is the scenario I want the output as 1. 0. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. 2188940092. You can't use aliases you created in the SELECT clause elsewhere in the same SELECT clause, so you need to place your FIRST_VALUE() and LAST_VALUE() functions within the DATEDIFF() function:. 2 Answers. The days are in two different, adjacent months, so the answer is 1 month difference. If date1 and date2 are either the same days of the month or both last days of months, then the result is always. 25 = 0. Viewed 4k times 1 I have a table with below structure. (Oct 10, 2006 - June 14, 2005 = 69) In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. select trunc ( (sysdate - to_date ('2012-02-28 15:20', 'YYYY-MM-DD hh24:mi')) / 24) from dual; You should have multiplied by. I am looking for solution how to select number of days between two dates without weekends and public holidays. Calculate the difference between two dates. SELECT startDate, endDate, DATEDIFF( endDate, startDate ) AS diff_days, CAST( months_between( endDate, startDate ) AS INT ) AS diff_months FROM yourTable ORDER BY 1; There are also year and quarter functions for determining the year and quarter of a date respectively. Sorted by: 0. date. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. id (SELECT SUM(DATEDIFF(HOUR, a. The previous example can be changed to get the days, hours, minutes and seconds between two dates using:Returns 'Oracle Database 10g Enterprise Edition Release 10. If date1 and date2 are either the same days of the month or both last days of months, then the. . SQL DATEPART. Oracle/PLSQL: MONTHS_BETWEEN Function 2. Computes the number of months between <date_1> and <date_2>. SELECT TIMESTAMPDIFF (MONTH, '2012-05-05', '2012-06-04') -- Outputs. DATEDIFF() Returns the difference between the two dates. This will return an interval that may look something like “1 year 2 months 3 days”. 365 / 365. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. Introduction. If you only need an approximation then you could just calculate the number of days difference and divide by 30. oracle difference between two dates in years Code Example. To break the diff between 2 dates into days, hours, minutes, sec -- you can use the following: Dy gives you number of days between 2 dates (partial days discarded). This command prints the order date in the specified format. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. Oracle offers its own solution, although does not have the DATEDIFF function. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. This post has been answered by 630199 on Jun 1 2009. For example, with some sample dates: select months_between (date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ---------- 38. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. Examples. You've told it to compare the. Example 1: Fetching Employees who Joined Between Certain Dates. The basic approach to show all duration units for a period is: Find the complete. event_id, evnt. Datediff (cast ('2020-08-01' as Date),Cast ('2020-07-31' as Date)) => 1. In a table called ‘Employees’ with columns ‘EmployeeID’, ‘Name’, and ‘HireDate’, we can calculate the number of months since each. Improve this answer. 1. SELECT DATEADD ( quarter, DATEDIFF. DateDiff function and I think it may have a parameter for indicating "in months" . The TIMESTAMPDIFF function returns an estimated number of intervals of the type that is defined by the first argument, based on the difference between two timestamps. 9. I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. This can have results that you are not expecting. 0208 days. for example Feb-15th to Mar-15th is a month. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. SELECT DATEADD ( year, DATEDIFF ( year, 0, GETDATE ()), 0 ) 這個 SQL 的技巧是先取得和 1900-01-01 - 也就是上面的 0 的意思，SQL Server 中的第零天 - 差幾年 (從 DATEDIFF 得到一個整數)，再用 DATEADD 加 0 來將整數再轉成日期的型態。. Modified 3 years, 4 months ago. 000000. Select Sysdate-Birth_date from Employees; the query return the number of days between the two dates. In short. Conversion between time units is also allowed; you can add, subtract, or compare dates by using days and state. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. FLOOR (DATEDIFF (DAY, date_of_birth, reference_date) / 365. I have a data field in my table that i would to use within my WHERE clause, to get the last 12 months dataset so for example, WHERE date between '20110323' and '20100323' Is this possible? I know I have to use something like GETDATE() or something but not quite sure how to incorporate this. Arguments. January 30, 2004 - 7:26 pm UTC. startdate, SYSDATE) Keep in mind that MONTHS_BETWEEN() will return fractions of months, so use TRUNC() or ROUND() if you need an integer number. So, Feb-28 to Mar-28 is a month. You also wouldn't prefix a function name with the @ sign. Here is my datediff function code. The screenshot below shows the data I want as well as the incorrect month between results I am obtaining. Date Part Flexibility: Years, months, days, hours, minutes, and seconds are among the date parts that are supported. Join our newsletter and get access to exclusive content every month. Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. 2425): datediff (day, {start-date}, {end-date},) / 365. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. 8. 0425. eps Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. SS, which computes the difference in seconds. The following example illustrates how to use the. The application passes in two parameters: a string representing the number of the desired month (i. 21. maybe something like passing an "m" as one of the parameters. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input. 6. Application. Oracle offers its own solution, although does not have the DATEDIFF function. It works if my beginning date is the first of january and the end date the 31st of December, but does not if it stars somewhere else during the year. Follow edited Apr 7, 2020 at. unit: The unit can be one of the following options: FRAC_SECOND (microseconds), SECOND, MINUTE, HOUR, DAY, WEEK, MONTH, QUARTER, or YEAR. Syntax¶ MONTHS. datediff (q,start date,end date) i. last_day (feb) to last_day (mar) is also commonly accepted as a "month". For example. date_from, evnt. The return type is always DATE, regardless of the datatype of date. Label the column Years worked. 5 = 0. I have a creation date column in the table. Outputs the fraction of days between two dates: DIFFERENCE ---------- 1. here i am trying get the month differences between two. , YEAR, MONTH, DAY,. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. oracle; datediff; or ask your own question. DECLARE @date datetime2 = '2021-01-07 14:36:17. 3. Add a number of months (n) to a date and return the same day which is n of months away. Value)/30. Example. FROM HR. 1 Answer. CancelDate IS NOT NULL THEN (CONVERT(NVARCHAR(MAX), DATEDIFF(day, Trips. July 16, 2013 at 3:32 pm. These are already in hour:minute:second format! with rws as ( select timestamp'2017-03-01 01:00:00' t1, timestamp'2017-03-01 02:34:56' t2 from dual ) select t2-t1 diff_interval from rws; DIFF_INTERVAL +00 01:34:56. The result is formatted according to the Format parameter. 365 / 365. user637544 Jun 1 2009 — edited Jun 1 2009. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. 2. startdate or. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. Viewed 2k times 1 I need to calculate the number of days between two dates as decimal, excluding the weekends and holidays by using a custom function in Oracle SQL. For example, this function returns 1. DATEDIFF calculates the difference between two dates - it doesn't add day or months to an existing date. Modified 11 years, 3 months ago. If you subtract from one date other you will get a count of days between this two dates. oracle. Multiply the result of step 1 by 12 to transform it to months 3. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. In SQL Server, the DATEDIFF function. I m used to sql server. select datediff (q,'03-30-2005','04-01-2005') will return 1. Oracle and MySQL support the SQL92 function EXTRACT, as in EXTRACT(MONTH FROM whn). This function is used to find the difference between two specified values of date. OutSystems can use both Oracle and MSSQL as its primary database. Modified 9 years ago. . A) Get the difference in months of dates on the same day The following example returns a difference in months between two dates: July 01 2017 and January 01 2017: SELECT MONTHS_BETWEEN ( DATE '2017-07-01', DATE '2017-01-01' ) MONTH_DIFF FROM DUAL; Code language: SQL (Structured Query Language) (sql) The result is 6 months as shown below: SQL> with 2 test (start_date, end_date) as 3 (select date '2020-10-01', 4 date '2020-11-02' 5 from dual 6 ), 7 calendar as 8 (select start_date + level - 1 datum 9 from test 10 connect by level <= end_date - start_date + 1 11 ) 12 select to_char(datum, 'yyyy. DATE_ADD () Add time values (intervals) to a date value. 3. created_date - adhh. 0. 850". Follow answered Oct 5, 2009 at 15:32. . In the empty box, enter the date format that you want to use. 0. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. If I've got it right. getMonth (); int m2 = date2. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. (floor ( (Base_DateDiff + 0 + Start_WeekDay) / 7)) counts the number of sundays. Click on the function name to jump to a discussion of that function. 2. 7. Asked 9 years, 3 months ago. subtract and give the difference in number of months. So, the weird number you see is the difference between the two dates. In PostgreSQL, you can take the difference in years, multiply by 12 and add. Hi, Everyone, I am trying to find out the difference in days between two dates and the query i am passing is SELECT TO_char(sysdate, 'dd/mm/yyyy')-TO_char('15/11/2011', 'dd/mm/yyyy') DAYS FROM DUAL. Add a number of months (n) to a date and return the same day which is n of months away. But it only for the date not for the time so i will be glad to know how to unite the two int columns + and convert it to date type for time difference. E. This does it excluding the days out but date part rather than description. Getting the 1st day of the month is simpler: select dateadd (day,- (day (current_timestamp)-1),current_timestamp) From your reference point-in-time, subtract (in days), 1 less than the current day-of-the-month component. This field level rule lets you display the difference between two dates. , year, quarter, month, day, hour, minute, second), startdate is the starting date or time, and enddate is the ending date or time. Before using this function, you must set the NLS_DATE_FORMAT parameter to display 24-hour time. For instance, select datediff (day,'1 Jan 2000' ,'18 April 2014') / 365. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. . date_to) - (DATEDIFF(WK, evnt. You are dividing datediff / 30 which is integer division, the result will be an int. answered May 15, 2013 at 7:21. SELECT purch_id, (trunc (sysdate, 'YYYY') + interval '11' month + interval '24' day) - purch_date days_to_christmas FROM CS260USER. 0. For the last row return the calculated date. dp_monthは、入力日付を取得する月間の距離を返します。 (2006年10月) - 2005年6月= 16) dp_weekは、入力日付を取得する週間の距離を返します。 各標準カレンダ週は日曜日に始まり、7日にまたがるように定義されています。 (2006年10月10日 - 2005年6月14日= 69)The result only contains the year, month and day, not the time. Delaying Execution. An expression that returns a value that is a built-in SMALLINT or. Exhibit A: John Doe has served since Feb 10, 2016. Here's the code provided by Tom Kyte at. datediff ('MONTH', pr. Examples of Results in Months. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. In my opinion the date diff is kind of subjective, especially on days. Beneath the plainness of its name, it hides a little depth. 365 days elapse between the two dates. You could always create your own custom function in the module: Function MonthDiff (startdate, enddate) ' return number of months between two dates. Months "m" Quarters "q" Years "y" firstWeekDay (default value is 1) is a parameter that can be used if you are returning the length of time in weeks. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. It counts the number of year boundaries between two dates. This can have results that you are not expecting. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is. Conversion among time units is also allowed; you can add, subtract, or compare dates by using days and state. by the way, Just new in DBeaver. Instead, use the dateAdd function on todays date, and compare the database table column to the result of that single calculation. It has column UPDATED and CREATED. mm') 16. Then it would also be helpful to be able to remove holidays from this. A custom option dialog displays with an empty box. DP_MONTH returns the distance between the months capturing the input dates. The function will always return the difference between two dates in days. g. StartDate, SYSDATE) you would use: MONTHS_BETWEEN(pr. MONTHS_BETWEEN = 1. 3. Dates are always a joy to work with in any programming language, SQL not excluded. As another option you could use the months_between () function, and manipulate the value that gives you into the three. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. Improve this answer. (Quarter 4, 2006 - Quarter 2, 2005 = 6) DP_MONTH returns the distance between the months capturing the input dates. 0. Share. 0. Tarek Fathy Nov 18 2010 — edited Nov 18 2010. Modified 9 years, 7 months ago. e it takes the quarter in which the start date exists and subtracts it from the quarter in which the end date exists. 8. Admission_Date < ADD_MONTHS (sysdate, -5) which could still use an index on that column, if there is one. In Oracle, you can subtract any number of days simply by subtracting that number from the current date. – user330315. If they are identical down to the second then, presumably, returning 0 is the right answer. In SQL Database Dates, SQL is a computer language for retrieving and managing data in relational databases like MySQL, MS Access, SQL Server, MS Access, Oracle, etc. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. Syntax The syntax for the MONTHS_BETWEEN function in Oracle/PLSQL is: MONTHS_BETWEEN ( date1, date2 ) Parameters or Arguments date1 The first date used to calculate the number of months between. Oracle Fusion Global Human Resources Cloud Service - Version 11. We need to pad a zero for single-digit months. %DateAdd . 33 shows the available functions for date/time value processing, with details appearing in the following subsections. 365 days elapse between the two dates. COMPUTE days3 = CTIME. should work fine. 2. – user330315. As you can see the EOMONTH function takes into account leap year. Step 4: Change Data Type. But your query is giving the last date of previous month. This page provides you with the most commonly used Oracle date functions that help you handle date and time data easily and more effectively. 1. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. I am looking for a way to implement the SQLServer-function datediff in PostgreSQL. You should consider how many. Refer to the tables below to determine the formats you can enter in the box. Sum (r => EF. January 1 of any year defines the starting number for the week datepart, for example: DATEPART (wk, 'Jan 1, xxxx') = 1, where xxxx is any year. startdate, SYSDATE) Keep in mind that MONTHS_BETWEEN. I want to calculate the current Age from Date of Birth in my Oracle function. EXE. Extract a value of a date time field e. CASE WHEN a. For formatting functions, refer to Section 9. The interval of time to use to calculate the difference between date1 and date2. In pseudocode I would do: offset = ( (today. 2903225806 DATE_DIFF =. If date1 is earlier than date2, then the result is negative. Its answer is 2014-08-17. PROJECT_TYPE, PROJECT. Share. 2258064516. 3. Just out of curiosity, have you paid the $95 for a manual yet? ;-) If not, get the thicker one when you do unless you are pretty familiar with the commands and just need a reference. g. trunc ( months_between ( end_date, start_date ) /12 ) Years, mod ( trunc ( months_between ( end_date, start_date ) ), 12 ) months, end_date - add_months (start_date,trunc ( months_between (end_date,start_date) )) days. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. The Question asked for "6 months from the system date". Click on any table field/column. As you can see it means that month. Javascript. Answer: Oracle supports date arithmetic and you can make expressions like "date1 - date2" using date subtraction to get the difference between the two dates. 2. Functions. Use DATEADD and DATEDIFF() function together in SQL query. TIMESTAMPDIFF ( numeric-expression string-expression. This post has been answered by 630199 on Jun 1 2009. 0 months apart:Asked 3 years, 4 months ago. The schema is SYSIBM. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. 2 Answers Sorted by: 7 Why do you believe that it is not a good idea to subtract two dates to get the number of days between them? That's certainly the. The date argument is a DATE value (or an expression that resolves to a DATE value) that should be rounded. If day number from start date is higher than day number from current date: days are negative. Viewed 43k times 0 I want to. Can Any one help me please. début)/365) Here is my table and the result in the 'montant_annuel' column:The datediff function make my query run very slow (16s for 11 records), and cost also very high (~43k). The numbers to the left of the decimal point are the days, the numbers to the right is the decimal fraction. This post has been answered by BluShadow on Nov 18 2010. Share. SELECT datediff ( TIMESTAMP '1981-04-01 10:11:13', TIMESTAMP '2022-04-03 17:48:09') as diff FROM DUAL; Outputs: DIFF. For example, using the standard SCOTT. 005479 0. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). 2. Answer: You can use the months_between function and convert it easily yo years between and decades between two dates: months_between/12 = years between. So subtracting a TIMESTAMP WITH TIME ZONE that is 5 am Eastern from a TIMESTAMP WITH TIME ZONE that is 2 am Pacific will result in an interval of 0. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. We will use the below date for the examples. If you want to confirm, simply run this. hourBegin, a. date_part is the part of date e. The two date fields are "timestamp" format (date and time). dividing by 365. When a user enters JAN 2009 - I want the worksheet to show data from Jan, Feb, Mar, Apr, May and June (2009). 29 Answers. 2. Second option is wrong when start hours/minutes/seconds is less then end. by: sandy | last post by: Hi, Using Java script I am trying to create code where when you place in the start date it automatically calculates 6 months for the experations date. Asked 10 years, 2 months ago. Teams. DATEDIFF (datepart, startdate, enddate) which can return the difference in years, months, days etc. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. Then use these rules to set the column values: Start date: for the first row, return the input date; otherwise return the first of the month; End date: get the month start for the next row and subtract one day from it. month ( [bd]) > month (getdate ())Oracle is an object-relational database management system. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). (floor ( (Base_DateDiff + 1 + Start_WeekDay) / 7)) counts the number of saturdays. Tip. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). Modified 6 years, 5 months ago. Modified 2 years, 9 months ago. Converting a raw number of days into a number of weeks and days is pretty simple. This gets the year difference between the birth date and the current date. If you want an integer. DATE_SUB () Subtract a time value (interval) from a date. 25)) AS `numberofemployees`. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. So I'm guessing it is an available function for mysql, but not for oracle databases. InDays) - (Pattern. EXTRACT (DAY from (first_date - second_date)) If for some reason, you do want to do that, then I don't think there is a datatype for the "datefield" keyword (YEAR, MONTH, DAY, etc). SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. Just divide the total by 7 to get the weeks and then calculate the remaining days. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . T was trying do calculate age as on todays date in ORACLE but after a lot of brain storming i didn't get it. I believe you want: Select id, datediff (day, min (hire) max (hire)) as Difference From Employees group by id having count (terminated) < count (*) -- at least one NULL value. Is there any simple way to calculate this in sql server 2005 . SQL Server ignores that this is just one day. mysql> SELECT something FROM tbl_name-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col; The query also selects rows with dates that lie in the future.